Question

I am working with a script for resizing images. I seem to be getting an error:

Error: no image was specified
Probably because of this code in the script(image.php):

    if (!isset($_GET['image']))
    {
        header('HTTP/1.1 400 Bad Request');
        echo 'Error: no image was specified';
        exit();

}

Here is what I’m doing(profile.php):

$your_image = $row['Image'];
$path_to_image = $row['PortraitPath'];
$width = 100;
$height = 100;

echo "<img src=\'/image.php/{$your_image}?width={$width}&amp;height={$height}&amp;cropratio=1:1&amp;image={$path_to_img}\' alt=\'Alt text goes here.\' />";

Therefore, I am reading $your_image and $path_to_image from a MySQL table, and then putting it in the img source. As mentioned above, obviously, image is not set, that is why I am getting that first error. What I don’t get is, how will the image actually even be set with my img src code? Aren’t I simply displaying the actual image? Then how will image even be set if a picture is simply being displayed? Thank you.

Answer 1

If you want to source a php file instead an image, you need to tell your php file that the output will be an image.
You can do this using the php header() function, like this:

header('Content-type: image/jpeg');

Here is some reference: php header function

About the address you are point to, isn’t a bit weird? You have a slash right after the .php, which suggest that you are trying to access some folder… Did you tested this url to see if a real image are being outputted on the screen?

Hope this can help you =)