Question

I am working with an Ajax imageuploader from this SITE. I currently achieve in creating duplicate preview images: one appears under the input field and the other will appear somewhere else in the page under something like “this what you chose”. The problem is that if the user selects a file, the function will display the Image but if the user changes its mind and chooses a new image then the yourCustomPreview will show the new image chosen and the old.

Is there a way of just having the most recent preview picture shown without the old preview picture appearing? If unclear please check the source files HERE

uploaderPreviewer.js- Original function

<script>
function displayImage($previewDiv, imageUrl) {

    var imageFilename = imageUrl.substr(imageUrl.lastIndexOf('/') + 1);

    $previewDiv
        .removeClass('loading')
        .addClass('imageLoaded')
        .find('img')
        .attr('src', imageUrl)
        .show();
    $previewDiv
        .parents('table:first')
        .find('input:hidden.currentUploadedFilename')
        .val(imageFilename)
        .addClass('imageLoaded');
    $previewDiv
        .parents('table:first')
        .find('button.removeImage')
        .show();
}
</script>

uploaderPreviewer.js- Modified function

<script>
    function displayImage($previewDiv, imageUrl) {
    //New
    var yourCustomPreview = $('#custompreview');

    var imageFilename = imageUrl.substr(imageUrl.lastIndexOf('/') + 1);

    $previewDiv
        .removeClass('loading')
        .addClass('imageLoaded')
        .find('img')
        .attr('src', imageUrl)
        .show();
    $previewDiv
        .parents('table:first')
        .find('input:hidden.currentUploadedFilename')
        .val(imageFilename)
        .addClass('imageLoaded');
    $previewDiv
        .parents('table:first')
        .find('button.removeImage')
        .show();

        //New
        yourCustomPreview.append('<img src="' + imageUrl + '"/>');

    }
</script>

Answer 1

ok, try this:

TO EDIT:

replace the displayImage function with this:

function displayImage($previewDiv, imageUrl) {
//New
var yourCustomPreview = $('#custompreview');
var imageId = $($previewDiv.context).attr('id');
var imageFilename = imageUrl.substr(imageUrl.lastIndexOf('/') + 1);

$previewDiv
    .removeClass('loading')
    .addClass('imageLoaded')
    .find('img')
    .attr('src', imageUrl)
    .show();
$previewDiv
    .parents('table:first')
    .find('input:hidden.currentUploadedFilename')
    .val(imageFilename)
    .addClass('imageLoaded');
$previewDiv
    .parents('table:first')
    .find('button.removeImage')
    .show();

    //New
    if(!yourCustomPreview.find('#' + imageId +'_prev').length > 0)
    {
      yourCustomPreview.append('<img id="' + imageId + '_prev" src="' + imageUrl + '"/>');
    }
    else
    {
      $('#' + imageId +'_prev').attr('src', imageUrl);
    }
}

TO DELETE

replace removeImage function with this:

function removeImage($removeImageButton, errorDisplayed) {

    var thumbIdToDelete = $removeImageButton.parents('table').find('[name=imageToUpload]').attr('id');
    var $parent = $removeImageButton.parents('table:first').parent();

    $.post($.uploaderPreviewer.removeImageAjaxUrl, {
        currentUploadedFilename: $parent.find('input:hidden.currentUploadedFilename').val()
    });

    $parent.find('input:hidden.currentUploadedFilename').removeClass('imageLoaded');
    $parent.find('div.previewImage')
        .removeClass('loading imageLoaded')
        .find('img')
        .hide();

    $parent.removeErrorMessage();

    if ( ! errorDisplayed) {
        $parent.find('input:file').val('');
        $removeImageButton.hide();
    }

    $('#' + thumbIdToDelete +'_prev').remove();
};