Question

I am working with an order system that has two tables Order and OrderLine pretty standard stuff. I want to work out an order line number for the order lines with respect to the order e.g.

Orderid Orderlineid linenumber
1          1              1
2          2              1
2          3              2
3          4              1
4          5              1
4          6              2

The OrderLineId is an identity column. I don’t want to store the line number as data in the database for two reasons. First there are already a great many existing orders and lines in the system and retrospectively adding the data is a headache I wish to avoid. Second if the user deletes a line then I would need to recalculate the line numbers for the whole order.

In SQL 2005 I can do this easy peasy using the ROW_NUMBER function.

Select Orderid, OrderLineid, ROW_NUMBER()  OVER(PARTITION BY Orderid ORDER BY Orderlineid) as LineNumber FROM OrderLine 

Is there anyway I can do this in SQL 2000?

The closest I found was a ranking function (see below) but this counts orders not lines.

SELECT x.Ranking, x.OrderId FROM (SELECT (SELECT COUNT( DISTINCT t1.Orderid) FROM orderline t1 WHERE z.Orderid >= t1.Orderid)AS Ranking, z.orderid  FROM orderline z ) x  ORDER BY x.Ranking 

Answer 1

You can use something like this:

select      ol1.orderId,     ol1.orderLineId,     count(*) as lineNumber from      orderLine ol1     inner join orderLine ol2          on ol1.orderId = ol2.orderId         and ol1.orderLineId >= ol2.orderLineId group by      ol1.orderId,      ol1.orderLineId