Question

I am working with dictionaries in python.

s = {'k1':['aa', 'bb', 'cc', 'dd', 'ee', 'ff', 'gg']}

I have created code as :

d = {}
for values in enumerate(s.values()[0]):
    if values[0]<2:
        d[values[1]] = 'True'
    else:
        d[values[1]] = 'False'

Can I convert this into one liner code using list comprehension or lambda?

I need answer as :

{'aa': 'True', 'bb': 'True', 'cc': 'False', 'dd': 'False', 'ee': 'False', 'ff': 'False', 'gg': 'False'}

updated – sry code typing mistake

Answer 1

In response to:

d = {}
for values in enumerate(s.values()[0]):
    if values[0]<2:
        d['ans'] = 'True'
    else:
        d['ans'] = 'False'

the one liner is:

d = {'ans': str(len(s.values()[0]) < 2)}

What you are doing is nonsensical. Essentially the code you posted will always set d['ans'] to 'True' when s.values()[0] has a length less than 2 (else 'False'). This is because the first element in the 2-tuple yielded by enumerate is the index (which you are comparing with <2). For all cases where the length of list is greater than 2, the else clause will keep setting it to 'False'. You dont even need a loop for this.

Update:
For your new version:

d = dict( [(val, str(index < 2)) for (index, val) in enumerate(s.values()[0])] )

or

d = dict( [(i , "True") for i in li[:2]] + [(i, "False") for i in li[2:]] )

update 2: or if you want to update an existing dictionary:

d.update( (( (val, str(index < 2)) for (index, val) in enumerate(s.values()[0]) )) )