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Home/ Questions/Q 8526943
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T08:24:55+00:00 2026-06-11T08:24:55+00:00

I am working with std::shared_ptr and during my software development I met a couple

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I am working with std::shared_ptr and during my software development I met a couple
of cases that let me doubt about memory management. I had a third party library that
gave me always raw pointers from functions and in my code I was transforming them
into std::shared_ptr (from std and not from boost. By the way what is the difference between
the two?). So let’s say I have the following code:

ClassA* raw = new ClassA;
std::shared_ptr<ClassA> shared(raw);

What happens now when the shared pointer goes out of scope (let’s say it was declared locally in a function
and now I am exiting the function). Will the ClassA object still exist because a raw pointer
is pointing to it?

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  1. Editorial Team
    Editorial Team
    2026-06-11T08:24:57+00:00Added an answer on June 11, 2026 at 8:24 am

    No it won’t. By giving the raw pointer to the shared_ptr, you are giving shared_ptr the responsibility of deleting it. It will do this when the last shared_ptr object referencing your ClassA instance no longer exists. Raw pointers don’t count.

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