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Asked: May 11, 20262026-05-11T02:09:53+00:00 2026-05-11T02:09:53+00:00

I am writing a client/server app in C++ and need to realize simple protocol

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I am writing a client/server app in C++ and need to realize simple protocol to sent and receive data correctly. I have a class for server protocol which can convert the message to my format and then convert it again from this format.
That what is server-side protocol looks like:

class BaseProtocol { protected:     int NumberOfBytesInPackOfText;     std::string serviceString; public:     BaseProtocol(int SizeOfTextPack, const char* extraString):          NumberOfBytesInPackOfText(SizeOfTextPack),              serviceString(extraString) {}     virtual std::string& convertToSystemMessage(const char* message)=0;     virtual std::string& convertToNativeMessage(const char* message)=0;     virtual ~BaseProtocol() {         NumberOfBytesInPackOfText = 0;         serviceString = '';     } };  class SimpleProtocol: public BaseProtocol { public:     SimpleProtocol(int SizeOfTextPack, const char* service):          BaseProtocol(SizeOfTextPack, service) {}     std::string& convertToSystemMessage(const char* nativeMessage);     std::string& convertToNativeMessage(const char* systemMessage); }; 

Now I can not decide what will be the better decision to make to implement that protocol on client application. A friend class to the server protocol? Or may be I need to extract subclass from server protocol and then the client protocol will be derived from this class?

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  1. 2026-05-11T02:09:54+00:00Added an answer on May 11, 2026 at 2:09 am

    I would create a protocol class independent of both the client and the server. They can each call the functions of that class rather than inheriting from the class.

    This follows the principle of favoring composition over inheritance. Also, neither the client nor the server ‘is a’ protocol interpreter. Rather, they each simply need to use the protocol.

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  • added an answer Well it sounds like the data is just inappropriate, and… May 11, 2026 at 3:56 pm
  • added an answer You're missing the required typename keyword: typedef typename container::value_type elementtype;… May 11, 2026 at 3:56 pm
  • added an answer In that case, where you’re squashing the exception, none. @finally… May 11, 2026 at 3:56 pm

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