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Home/ Questions/Q 7009417
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T21:51:34+00:00 2026-05-27T21:51:34+00:00

I am writing a function that will take a parameter and, among other things,

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I am writing a function that will take a parameter and, among other things, make a dictionary. I would like the dictionary’s name to be based off the name of the input file. Say ht input file is input.xml , i would like the name of the dictionary to be input. Ideally I would use something like this:

def function(input):
    for x in y: list(get value)
    input[:4][key] = [value]

I am wondering if you know a better way to do this but what i am using now is an extra name in the function:

def function(input, dictname):
    for x in y: list(get value)
    dictname[key] = [value]

right now I am simply adding a second name to my function but am wondering if there is a way to do this to require fewer inputs.


Edit


I am including a longer version of the function I am using so you guys can get the context. This uses a BioPython module to iterate through an XML file of hits. I am using [temp] to hold the hits for each query and then making a dictionary of for each set of query/hits. I would like this dictionary to be named the same as my input file.

from Bio.Blast import NCBIXML

def make_blast_dictionary(blastxml, maxhits, blastdict):
    temp=[]
    for record in NCBIXML.parse(open(blastxml):    
        for number, align in enumerate(record.alignments):
            if number == int(maxhits): break
            temp.append(str(align.title).split("|")[1])
    blastdict[str(record.query_id)] = [temp]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T21:51:35+00:00Added an answer on May 27, 2026 at 9:51 pm

    The thing about named variables is that you can call them whatever you like. It’s best to name them specific to the context you’re using them with.

    It would be a better move to simply return a dictionary from your method, instead.

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