Question

I am writing a if statement that if the two dates listed are equal it echo’s the first date and if the they aren’t(else statement) it echoes “date1-date2” I have it inside a function and I do not know if I am alowed to do that.Here is the error I am getting

Parse error: syntax error, unexpected T_IF

Here is my function:

function getfevent ($conn) { 
$sql = "SELECT `name` FROM `event` WHERE `featured` = 0 LIMIT 0, 30 ";
$statement=$conn->prepare($sql); 
$statement->execute(); 
while($row=$statement->fetch()) {
$eventname = $row['name'];
$row_id=geteventid ($conn,$eventname);
$row_end=geteventend ($conn,$eventname);
$date=if ($row_id == $row_end){
    echo $row_id;
}
    else {
    echo $row_id " - " $row_end; 
}
?>
<?php echo "<td>$eventname</td><td>$date</td></tr>"; ?>
<?php
} 
} 
getfevent($conn);

Answer 1

Probably you want this.

$date = $row_id == $row_end ? $row_id : $row_id . " - " . $row_end;
echo $date;

Don’t forget. Use . to concat.

It’s the same of

if ($row_id == $row_end) {
    $date = $row_id;
} else {
    $date = $row_id . " - " . $row_end;
}