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Home/ Questions/Q 6913259
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:11:43+00:00 2026-05-27T09:11:43+00:00

I am writing a logger. If disabled, this is the code which defines the

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I am writing a logger. If disabled, this is the code which defines the LOG macro:

#ifdef NO_LOG

#include <ostream>

struct nullstream : std::ostream {
    nullstream() : std::ios(0), std::ostream(0) {}
};

static nullstream logstream;

#define LOG if(0) logstream

#endif

LOG << "Log message " << 123 << std::endl;

It works correctly. The compiler should completely remove the code related to the LOG macro.

However I would like to avoid the inclusion of ostream and define the logstream object as something really “light”, possibly null.

Thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T09:11:44+00:00Added an answer on May 27, 2026 at 9:11 am
    // We still need a forward declaration of 'ostream' in order to
    // swallow templated manipulators such as 'endl'.
    #include <iosfwd>
    
    struct nullstream {};
    
    // Swallow all types
    template <typename T>
    nullstream & operator<<(nullstream & s, T const &) {return s;}
    
    // Swallow manipulator templates
    nullstream & operator<<(nullstream & s, std::ostream &(std::ostream&)) {return s;}
    
    static nullstream logstream;
    
    #define LOG if(0) logstream
    
    // Example (including "iostream" so we can test the behaviour with "endl").
    #include <iostream>
    
    int main()
    {
        LOG << "Log message " << 123 << std::endl;
    }
    
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