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Home/ Questions/Q 7174353
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T16:01:21+00:00 2026-05-28T16:01:21+00:00

I am writing a method that will generate an unsigned int between 1 and

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I am writing a method that will generate an unsigned int between 1 and 6 (boundaries included). The current method I have is below.

        private static Random random = new Random();
        ...
        private static uint GetRandomChannel()
        {
            return Convert.ToUInt32(random.Next(1, 6));
        }

I’ve run this method a thousand times and I get numbers 1 through 5 but never get 6. Why is this happening and how can I fix it?

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  1. Editorial Team
    Editorial Team
    2026-05-28T16:01:22+00:00Added an answer on May 28, 2026 at 4:01 pm

    The second parameter to random.Next() is an exclusive upper bound.

    Parameters

    minValue: The inclusive lower bound of the random number returned.

    maxValue: The exclusive upper bound of the random number returned. maxValue must
    be greater than or equal to minValue.

    Return value

    A 32-bit signed integer greater than or equal to minValue and less than maxValue; that is, the range of return values includes minValue but not maxValue. If minValue equals maxValue, minValue is returned.

    This means that random.Next(1, 6) will only return values n in the range 1 <= n < 6.

    So for your die rolling simulation you will need to use

    random.Next(1, 7)
    

    Note: The design of this API is odd. It has special case handling for minValue == maxValue which seems to needlessly complicate the API. If I had designed this API I would have made both parameters be inclusive limits. This would have resulted in a pleasing symmetry and would have allowed random numbers that cover the full range of int.

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