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Home/ Questions/Q 202397
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:17:11+00:00 2026-05-11T17:17:11+00:00

I am writing a minimal replacement for mod_python’s publisher.py The basic premise is that

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I am writing a minimal replacement for mod_python’s publisher.py

The basic premise is that it is loading modules based on a URL scheme:

/foo/bar/a/b/c/d

Whereby /foo/ might be a directory and ‘bar’ is a method ExposedBar in a publishable class in /foo/index.py. Likewise /foo might map to /foo.py and bar is a method in the exposed class. The semantics of this aren’t really important. I have a line:

sys.path.insert(0, path_to_file)  # /var/www/html/{bar|foo}
mod_obj = __import__(module_name)
mod_obj.__name__ = req.filename

Then the module is inspected for the appropriate class/functions/methods. When the process gets as far as it can the remaining URI data, /a/b/c is passed to that method or function.

This was working fine until I had /var/www/html/foo/index.py and /var/www/html/bar/index.py

When viewing in the browser, it is fairly random which ‘index.py’ gets selected, even though I set the first search path to ‘/var/www/html/foo’ or ‘/var/www/html/bar’ and then loaded __import__(‘index’). I have no idea why it is finding either by seemingly random choice. This is shown by:

__name__ is "/var/www/html/foo/index.py"
req.filename is "/var/www/html/foo/index.py"
__file__ is "/var/www/html/bar/index.py"

This question then is, why would the __import__ be randomly selecting either index. I would understand this if the path was ‘/var/www/html’ but it isn’t. Secondly:

Can I load a module by it’s absolute path into a module object? Without modification of sys.path. I can’t find any docs on __import__ or new.module() for this.

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:17:11+00:00Added an answer on May 11, 2026 at 5:17 pm

    Can I load a module by it’s absolute
    path into a module object? Without
    modification of sys.path. I can’t find
    any docs on __import__ or new.module()
    for this.

    import imp
    import os
    
    def module_from_path(path):
        filename = os.path.basename(path)
        modulename = os.path.splitext(filename)[0]
    
        with open(path) as f:
            return imp.load_module(modulename, f, path, ('py', 'U', imp.PY_SOURCE))
    
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