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Home/ Questions/Q 6144051
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T18:36:02+00:00 2026-05-23T18:36:02+00:00

I am writing a python script 2.5 in Windows whose CurrentDir = C:\users\spring\projects\sw\demo\753\ver1.1\011\rev120\source my

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I am writing a python script 2.5 in Windows whose CurrentDir = C:\users\spring\projects\sw\demo\753\ver1.1\011\rev120\source my file is test.py. From this path I would like to access files in this path: C:\users\spring\projects\sw\demo\753\ver1.1\011\rev120\Common\

I tried using os.path.join but it does not work and I from the docs I understand why.
So what could be the best pythonic solution for this?

currentdir = os.getcwd()    
config_file_path =  os.path.join(currentdir,"\\..\\Common")
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  1. Editorial Team
    Editorial Team
    2026-05-23T18:36:02+00:00Added an answer on May 23, 2026 at 6:36 pm

    Your problem can be solved by using os.path.join, but you’re not using it properly.

    currentdir = os.getcwd()    
    config_file_path =  os.path.join(currentdir,"\\..\\Common")
    

    "\\..\\Common" is not a relative path, as it starts with \.

    You need to join with ..\\Common, which is a relative path.

    Please note that os.path.join is not a simple string concatenation function, you don’t need to insert the in-between antislashes.

    So fixed code would be :

    config_file_path =  os.path.join(currentdir,"..\\Common")
    

    or, alternatively :

    config_file_path =  os.path.join(currentdir, "..", "Common")
    
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