Question

I am writing a script that prints arguments starting with a vowel and end in a digit

Example : ./script Alex1GB0 Bud1GG0 Ethan8DC0 Chad5XZ7d

The output should be

Alex1GB0 Ethan8DC0 

This is what I have tried so far

 #!/bin/bash
 for x in $*; do
     o=$(echo $x | grep '\<[AEIOUaeiou]...[0-9].\>')

     if[$? -eq 0]; then
            echo $o
     fi
 done
 exit 0

It doesn’t work ; What should I change?

Answer 1

There is nothing like ellipsis (...) in bash. Instead, use .*. Also, the dot after [0-9] means there is something after the digit, which is against the specification.

In fact, there is no need to run a subshell and grep, when we have pattern matching:

#! /bin/bash
for x in "$@"; do
    if [[ $x == [AEIOUaeiou]*[0-9] ]] ; then
        echo "$x"
    fi
done