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Home/ Questions/Q 6943953
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:13:22+00:00 2026-05-27T13:13:22+00:00

I am writing a script to access a specific detail about the user and

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I am writing a script to access a specific detail about the user and I was hoping to make the database query be function.

function connectUser($ip) {
   $q = "SELECT * FROM users where ID='$ID'";
   $s = mysql_query($q);
   $r = mysql_fetch_array($s);
}

But when I try and use it it will not access the row the way I want it to.

$user = '999';
connectUser($user)
echo $r['name'];

But if I put echo $r[‘name’]; in the function it will work.

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:13:23+00:00Added an answer on May 27, 2026 at 1:13 pm

    That’s because the variable $r isn’t being returned by the function, so it’s never being set outside of the function. Here’s what you should have:

    function connectUser($ip) {
       $q = "SELECT * FROM users where ID='$ip'";
       $s = mysql_query($q);
       return mysql_fetch_array($s);
    }
    

    And then outside have:

    $user = '999';
    $r = connectUser($user)
    echo $r['name'];
    

    You might also want to take a look at this question: prepared statements – are they necessary

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