I am writing a script which must copy some names into a multidimensional array, print the contents of the array and then deallocate the memory and terminate. The problem I am having is that when I run the script it only prints out the last name entered. Here is what I have done. Any help would be great! Thanks in advance!
#include <iostream>
#include <string.h>
using namespace std;
void createArray(int n);
void addDetail(char*& name, char*& surname);
void printArray();
void clear();
char ***details;
int used;
int size;
int main()
{
createArray(3);
char* tmpName = new char[20];
char* tmpSurName = new char[120];
strcpy(tmpName, "nameA");
strcpy(tmpSurName, "surnameA");
addDetail(tmpName,tmpSurName);
strcpy(tmpName, "nameB");
strcpy(tmpSurName, "surnameB");
addDetail(tmpName,tmpSurName);
strcpy(tmpName, "nameC");
strcpy(tmpSurName, "surnameC");
addDetail(tmpName,tmpSurName);
clear();
return 0;
}
void createArray(int n)
{
details= new char**[n];
for(int i=0; i<n; i++)
details[i] = new char*[2];
size = n;
used = 0;
}
void addDetail(char*& name, char*& surname)
{
if(occupation < size)
{
details[used][0] = name;
details[used][1] = surname;
used++;
}else{
cout << "Array Full " << endl;
}
}
void printArray()
{
for(int i=0; i<used; i++)
cout << details[i][0] << " " << details[i][1] << endl;
}
void clear()
{
for(int i=0; i<size; i++)
{
delete [] details[i];
details[i] = 0;
}
delete [] details;
details=0;
}
You didn’t allocate memory for
details[used][0]anddetails[used][1]so it’s using whatever random address was in those locations.Since this is C++ you can use string instead perhaps?
std::string **details;. This should work with your existing code, except that it will leak memory.Better still is to use a vector of vectors.
Something like:
std::vector<std::vector<std::string> > details;Then the
createArrayfunction can go away completely andaddDetailbecomes simpler: