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Asked: May 10, 20262026-05-10T19:03:34+00:00 2026-05-10T19:03:34+00:00

I am writing a shell script that takes file paths as input. For this

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I am writing a shell script that takes file paths as input.

For this reason, I need to generate recursive file listings with full paths. For example, the file bar has the path:

/home/ken/foo/bar 

but, as far as I can see, both ls and find only give relative path listings:

./foo/bar   (from the folder ken) 

It seems like an obvious requirement, but I can’t see anything in the find or ls man pages.

How can I generate a list of files in the shell including their absolute paths?

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  1. 2026-05-10T19:03:35+00:00Added an answer on May 10, 2026 at 7:03 pm

    If you give find an absolute path to start with, it will print absolute paths. For instance, to find all .htaccess files in the current directory:

    find "$(pwd)" -name .htaccess 

    or if your shell expands $PWD to the current directory:

    find "$PWD" -name .htaccess 

    find simply prepends the path it was given to a relative path to the file from that path.

    Greg Hewgill also suggested using pwd -P if you want to resolve symlinks in your current directory.

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