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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:14:34+00:00 2026-05-27T10:14:34+00:00

I am writing a simple program, it writes I love Java 300 times to

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I am writing a simple program, it writes “I love Java” 300 times to a text file, and I have it working as shown.

public class PrintLines {
    public static void main(String[] args) throws Exception{    
         java.io.File file = new java.io.File("myFile.txt");
         java.io.PrintWriter output = new java.io.PrintWriter(file);        
         int count = 1;
         while (count <= 300) {
             output.println(count + " I love Java!");
             count++;           
         }
         output.close();
    }
}

What I am unsure about, and have been trying to figure out on several webpages and the text book I use for class, is how do I do a try/catch block for this code and still create the file? It works, as I said, but I have to do it without the throws Exception in there. Can’t find a decent webpage which gives newbie answers for beginning programmers like me.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:14:35+00:00Added an answer on May 27, 2026 at 10:14 am

    Your code should look similar to this.
    The EXCEPTION should be IOException, I think.

    public class PrintLines {
        public static void main(String[] args) {
            java.io.File file;
            java.io.PrintWriter output = null;
            try{
                file = new java.io.File("myFile.txt");
                output = new java.io.PrintWriter(file);
                int count = 1;
                while (count <= 300) {
                    output.println(count + " I love Java!");
                    count++;
    
               }
               output.close();
           } catch(*EXCEPTION*) {
           //Handle Exception
           } finally {
              if(output!=null) {
               output.close();
              }
           }
        }
    }
    
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