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Home/ Questions/Q 6218335
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T07:35:26+00:00 2026-05-24T07:35:26+00:00

I am writing an application in c++. I have an interface defined with various

  • 0

I am writing an application in c++.
I have an interface defined with various functions:

class ITest
{
public:
        virtual void x()=0;
        virtual void y()=0;
}

I then have a class that implements this interface, along with additional functions:

class NewClass: public ITest
{
public:
    virtual void x();
    virtual void y();
    // new function not defined in interface
    virtual void z();
}

I now want to access all of these 3 functions from my unit tests.
Currently I am using:

ITest* pTest;

which will only give me access to the 2 functions defined in the interface.
How can I also gain access to function z() without defining it in the interface?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T07:35:27+00:00Added an answer on May 24, 2026 at 7:35 am
    NewClass* p = dynamic_cast<NewClass*>(pTest);
    if(p==0)
    {
       //error!!! pTest's dynamic type wasn't NewClass*
    }
    else
    {
       p->z();
    }
    

    Instead of dynamic_cast, you can use static_cast. But if pTest‘s dynamic type is not actually NewClass* you’ll get undefined behavior.

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