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Home/ Questions/Q 3876056
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T22:20:16+00:00 2026-05-19T22:20:16+00:00

I am writing my first MSBuild script and ran into a problem. I have

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I am writing my first MSBuild script and ran into a problem.

I have several projects, defined in an itemgroup

<ItemGroup>
  <Projects Include="Project1Dir\Project1.csproj"/>
  <Projects Include="Project2Dir\Project2.csproj"/>
</ItemGroup>

Then, on deployment step, I am trying to do this:

The following should collect all the files for deployment into separate itemgroups for each project (“Project1deploymentFiles” and “Project2deploymentFiles”)

<CreateItem Include="$(WebPublishDir)\%(Projects.Filename)\**\*.*">
  <Output ItemName="%(Projects.Filename)deploymentFiles" TaskParameter="Include"/>
</CreateItem>

Thes line, should copy each project’s files into separate folder

<Copy SourceFiles="@(%(Projects.Filename)deploymentFiles)" DestinationFolder="$(DeploymentDir)\%(Projects.Filename)\%(RecursiveDir)\" />

But it seems that MSBuild resolves %(RecursiveDir) metadata to empty string, as all the files are copied to the same root folder (different for each project).

Any suggestions what am I doing wrong here?

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  1. Editorial Team
    Editorial Team
    2026-05-19T22:20:17+00:00Added an answer on May 19, 2026 at 10:20 pm

    I’ve found a solution myself:

    <CreateItem Include="$(WebPublishDir)\%(Projects.Filename)\**\*.*" AdditionalMetadata="ProjectDir=%(Projects.Filename)\">
      <Output ItemName="deploymentFiles" TaskParameter="Include"/>
    </CreateItem>
    
    <Copy SourceFiles="@(deploymentFiles)" DestinationFolder="$(DeploymentDir)\%(ProjectDir)\%(RecursiveDir)\" />
    

    Main idea here is to use one item for all projects and just add AdditionalMetadata to values, containing projectname

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