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Home/ Questions/Q 7868025
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T00:52:19+00:00 2026-06-03T00:52:19+00:00

I am writing my first Opa application. I am trying to set up a

  • 0

I am writing my first Opa application. I am trying to set up a match for url handling. Code is as follows:

function start(url) 
{
    match (url)
    {
        case {path:[] ...}: Resource.page("Home", home())
        case {...}: Resource.page("nofindy", nofindy())
    }
}
Server.start(Server.http, { dispatch: start })

It works like a charm, but now I want to be able to do synonymous mappings. For example, I would like to be able to not only have / go to the home page, but also /home.

Is there a concise way to do this, perhaps with an OR operator, or do I need to set up separate cases that both trigger the same resource?

tl;dr: is there a better way to write the following snippet:

case {path:[] ...}: Resource.page("Home", home())
case {path:["home"] ...}: Resource.page("Home", home())
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  1. Editorial Team
    Editorial Team
    2026-06-03T00:52:21+00:00Added an answer on June 3, 2026 at 12:52 am

    You should use a custom instead of a dispatch:

    function start(v){
       Resource.page(v, <h1>{v}</h1>)
    } 
    
    urls = parser {
       case ("/" | "/home") : start("home")
       case .* : start("other")
    }
    
    Server.start(Server.http, {custom: urls})
    

    Learn more about the parser here: http://doc.opalang.org/manual/The-core-language/Parser

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