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Home/ Questions/Q 579229
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T14:20:40+00:00 2026-05-13T14:20:40+00:00

I am writing to a framebuffer located at /dev/fb0. Everything works fine until I

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I am writing to a framebuffer located at “/dev/fb0”. Everything works fine until I try to write again to the pipe using an OutputStream, which hangs the program. I have resolved this by closing the output stream and then recreating it, but this seems awfully slow and blunt.


Framebuffer.java

public class Framebuffer extends Autobuffer {
private FileOutputStream out = null;
private File pipe = null;

public Framebuffer() {
   super(320, 240);
}

public Framebuffer(File pipe) {
   super(320, 240);
   try {
      out = new FileOutputStream(pipe);
   } catch (FileNotFoundException e) {
   e.printStackTrace();
  }
 this.pipe = pipe;
 }

 public void sync() throws IOException {
   out.write(getBytes());
   out.close();
   out = new FileOutputStream(pipe);
 }
 }

Any ideas?

Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-13T14:20:41+00:00Added an answer on May 13, 2026 at 2:20 pm

    Firstly, unless something really weird is going on, “/dev/fb0” is a device file not a pipe. [This is a nitpick, but if you use the wrong terminology, 1) people won’t understand you and 2) you will have difficulty searching for answers.]

    Secondly, this looks like a weird way to interact with a framebuffer!!

    I suspect that the problem is that you need to do the equivalent of a POSIX lseek call to set the stream position to zero each time you draw a frame. I’ve found two ways to do this:

    • Use RandomAccessFile instead of OutputStream / FileOutputStream, and call seek(long) to seek the file.

    • Call FileOutputStream.getChannel(), and then use position(long) to seek the file.

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