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Home/ Questions/Q 1002077
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T07:46:35+00:00 2026-05-16T07:46:35+00:00

I apologize as this is so simple, I was working with my own XOR

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I apologize as this is so simple, I was working with my own XOR swap method and wanted for the heck of it compare the speed difference between reference and pointer use (do not spoil it for me!)

My XOR ptr function is as follows:

 void xorSwapPtr (int *x, int *y) {
     if (x != y && x && y) {
         *x ^= *y;
         *y ^= *x;
         *x ^= *y;
     }
 }

I copied this to a xorSwapRef function which just uses refs (int &x, etc.) anywho:

I use it like this but I get the error error: invalid conversion from ‘int’ to ‘int*’

int i,x,y = 0;
for(i=0;i<=200000;i++) {
    x = rand();
    y = rand(); 
    xorSwapPtr(x, y); //error here of course
}

How would I use the pointer function with ints, like the ref one? I just wonder because the example xor function I found in a book uses pointers, hence my wanting to test.

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  1. Editorial Team
    Editorial Team
    2026-05-16T07:46:35+00:00Added an answer on May 16, 2026 at 7:46 am

    x and y are ints; xorSwapPtr takes two int*s, so you need to pass the addresses of x and y, not x and y themselves:

    xorSwapPtr(&x, &y);
    
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