Question

I ask for d->id to put it on the list, but if I ask for more than one, all the list items get the last one.

For example, if the for has 2 iterations and novo->prato[0] is "M1" (this is asked to the user) and novo->prato[1] is "M3", both positions stay "M3". Why?

Here is the code:

typedef struct pedido pedido, *ppedido;
typedef struct prato prato, *pprato;

struct pedido{
    char id[5];
    int prioridade;
    int mesa, n_pratos;
    pprato prato[TAM];
    ppedido prox;
};

struct prato{
    char id[5];
};

int verifica_prato(ppedido p,int j)
{
    FILE *f;
    struct item aux;

    int i=0;

    f = fopen("menu.bin", "rb");
    if(f == NULL){printf("O sistema nao consegue aceder a memoria");return;}

    while((fread(&aux, sizeof(struct item), 1, f)) == 1){
        if((strcmp(p->prato[j]->id, aux.id)) == 0)
            i++;
    }
    fclose(f);

    if(i == 0){
    printf("Prato nao existe no menu.\n");
    return 1;
        }

    if(i > 1)
    return 0;
}


for(i=0;i<novo->n_pratos;i++){
        do{
            printf("ID do prato %d: ", i+1);
            scanf("%s", &d->id);
            novo->prato[i] = d;
            k = verifica_prato(novo,i);

        }while(k != 0);
    }

Answer 1

You are assigning the pointer to structure d when you do novo->prato[i] = d ,
so each time you make a change to d it would be reflected at novo->prato[i] since all values in prato array is pointing to the same address i.e. d.

I’m not exactly sure what you intend to do but one way could be to malloc d every time in loop before asking the user for input. Remember you also need to look into ‘freeing’ the memory prato[i] eventually.