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Home/ Questions/Q 9201055
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T22:54:46+00:00 2026-06-17T22:54:46+00:00

I basically have 2 list of the same object type. The first one (A,B,C,D)

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I basically have 2 list of the same object type.
The first one (A,B,C,D) is a property of one of my objects.

I need to join the second list(B, E, F) in my object, but exclude the duplicates.

This means i can’t just do:

    ListA.AddRange(ListB)

I’ll have to change it to

    ForEach item in ListB
       If Not ListA.Contains(item)
          ListA.Add(item)
       EndIf
    Next

Or add:

    ListA = ListA.Distinct()

Is there a faster and smoother way to code this?

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  1. Editorial Team
    Editorial Team
    2026-06-17T22:54:47+00:00Added an answer on June 17, 2026 at 10:54 pm

    If you have already overridden the Equals and GetHashcode you can use Enumerable.Union directly:

    var ListC = ListA.Union(ListB).ToList();
    

    Otherwise you could implement IEqulityCompararer<Foo> and use ListA.Union(ListB, comparer).

    Assuming Foo is the type of your class and Name is a property you want to use to detect duplicates.

    public class FooComparer : IEqualityComparer<Foo>
    {
        public bool Equals(Foo x, Foo y)
        {
            if (x == null || y == null) return false;
            // 'A' = 'a' just to demonstrate case-insensitive duplicates
            return x.Name.Equals(y.Name, StringComparison.OrdinalIgnoreCase);
        }
    
        public int GetHashCode(Foo obj)
        {
            if (obj == null) return int.MinValue;
            return obj.Name.GetHashCode();
        }
    }
    

    Now use this comparer for Union:

    var ListC = ListA.Union(ListB, new FooComparer()).ToList();
    
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