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Home/ Questions/Q 7052975
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T03:26:55+00:00 2026-05-28T03:26:55+00:00

I believe I understand that during macro expansion, a macro does not have access

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I believe I understand that during macro expansion, a macro does not have access to the things a function has access to, because expansion happens before compile time.

But, I am having trouble understanding is how to perform checks at macro expansion time.

For example:

(defn gen-class [cl-nam]
    (fn [cmd & args]
        (condp = cmd
            :name (name cl-nam))))

(defmacro defnclass [cl-nam]
    `(def ~cl-nam (gen-class '~cl-nam)))

I would like to check to see that cl-nam is not a sequence. I would like to use count and find out of its length is > 1.

I understand I can unquote the println in the following macro, so that I can get an expansion-time message.

(defmacro defnclass_info [cl-nam]
    `(do
        ~(println cl-nam)
        (def ~cl-nam (gen-class '~cl-nam))))

But, I am not sure how to go about checking to see what was passed for cl-nam.

I’m reading a lot of Clojure macro descriptions from several books, and am stumped.
Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-28T03:26:55+00:00Added an answer on May 28, 2026 at 3:26 am

    A macro is really just a function.

    (defmacro defnclass-info
      [cl-name]
      (when (seq? cl-name)
        (throw (Exception. "cl-name must not be a sequence")))
      `(def ~cl-name (gen-class '~cl-name)))
    

    Edit: One could also switch behaviour and recursively call the macro again for the whole list. What you do, depends on your requirements.

    (defmacro defnclass-info
      [cl-name]
      (if (seq? cl-name)
        `(do ~@(for [cn cl-name] `(defnclass-info ~cn)))
        `(def ~cl-name (gen-class '~cl-name))))
    

    The macro expansion is just what the “function” returns. So you have full flexibility on what you do with the macro arguments.

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