Question

I build a little script that parses a directory for files of a given filetype and stores the location (including the filename) in an array. This look like this:

def getFiles(directory)   arr = Dir[directory + '/**/*.plt']   arr.each do |k|     puts '#{k}'   end end 

The output is the path and the files. But I want only the path.

Instead of /foo/bar.txt I want only the /foo/

My first thought was a regexp but I am not sure how to do that.

Answer 1

Could File.dirname be of any use?

File.dirname(file_name ) → dir_name

Returns all components of the filename given in file_name except the last one. The filename must be formed using forward slashes (“/’’) regardless of the separator used on the local file system.

File.dirname('/home/gumby/work/ruby.rb') #=> '/home/gumby/work'