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Home/ Questions/Q 8690773
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T23:58:29+00:00 2026-06-12T23:58:29+00:00

I build this code which displays all entries of an array in queue fashion.

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I build this code which displays all entries of an array in queue fashion. The problem is that I was told that this could be done without for statement which rewind content of i to 0, but I can’t figure out how.

How else this could be done?

   public void display()
   {
       int i = frontIndex;

       while(true)
       {
           if (i == numberOfItems)
               i = 0;

           System.out.print(array[i++] + " ");

           if (i == rearIndex + 1)
               break;
       }
   }
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  1. Editorial Team
    Editorial Team
    2026-06-12T23:58:30+00:00Added an answer on June 12, 2026 at 11:58 pm

    You can use the % operator and print the i % numberOfItems:

    It is not tested, but it should be something along the lines of:

    for (int i = frontIndex; i % numberOfItems != rearIndex+1; i++) { 
       System.out.print(array[(i++) % numberOfItems)] + " ");
    }
    

    The idea is (array.length + k) % array.length == k, so using the % operator, is actually equivalent to resetting the index i back to 0.

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