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Home/ Questions/Q 7496879
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T18:49:53+00:00 2026-05-29T18:49:53+00:00

I call a function that stacks two async calls and calls a callback when

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I call a function that stacks two async calls and calls a callback when they have both completed.
I am using a really simple method to keep track of the calls that have not completed

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The problem is that the program exits before the operation of the two functions is complete. I noticed this was the problem when I was debugging and gave the process time to complete before it exits.

How can I fix this? (At the moment I am at a bit of a loss on how to exactly explain my problem please ask me anything you need to so I can clarify the question)

—–EDIT

With the script below why when I run it does it just exit? I thought that by calling on I was registering to the event que and the script should continue to run?

var events  = require('events');
var eventEmitter = new events.EventEmitter();

eventEmitter.on('spo',function(){
console.log('spo');
});
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-29T18:50:03+00:00Added an answer on May 29, 2026 at 6:50 pm

    COMING From a Git Hub thread.

    What keeps the event loop alive is handles (sockets, timers, etc.) of which your script has none.

    EventEmitter instances are synchronous – that is, they run immediately
    – so in your example, once the event has fired, the script is done.

    Think of it like this: an EventEmitter in itself isn’t useful, it only
    becomes useful when it’s tied to something that emits interesting
    events (data from the network or the file system, a timer that
    expires, etc.).

    I think that what they are saying is that it is the handle outside of Node into C land that holds the script open.

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