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Home/ Questions/Q 728603
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T06:42:01+00:00 2026-05-14T06:42:01+00:00

I call sortable.stop() to make an ajax call to store some data after drag

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I call sortable.stop() to make an ajax call to store some data after drag & drop operation.

When the ajax call returns an error (application logic error or net problem) I want to move the dragged element to its original/start position, how can I achieve it?

The scenario should be

  1. user drags A to B
  2. the sortable.stop() event is called, it triggers an ajax call
  3. the ajax call returns an error
  4. inside the stop() event we get the ajax error
  5. move A to its original position
  6. user again move A to B
  7. everything is ok
  8. A remains in its new position in B

Steps 6-8 are shown to clarify a successive drag can be done and previous error must be forgotten.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T06:42:01+00:00Added an answer on May 14, 2026 at 6:42 am

    Have a look at .sortable('cancel'); something like this:

    var list = $('#some-list')
    list.sortable(
    {
        // Some options.
        stop: function()
        {
            $.post('some-url', someData, function()
            {
                if (somethingWentWrong)
                {
                    list.sortable('cancel');
                }
            });
        }
    });
    
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