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Home/ Questions/Q 6330885
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:57:09+00:00 2026-05-24T17:57:09+00:00

I call those functions on href: function LoadDiv1() { var uri = ‘@this.Routes().Parts.Div1.FullUrl(Model.SignedInUser.User.Id)’; $(‘#home_content’).load(uri).css(display,

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I call those functions on href:

function LoadDiv1() {
       var uri = '@this.Routes().Parts.Div1.FullUrl(Model.SignedInUser.User.Id)';
       $('#home_content').load(uri).css("display", "none").fadeIn(500);
}
function LoadDiv2() {
       var uri = '@this.Routes().Parts.Div2.FullUrl(Model.SignedInUser.User.Id)';
       uri = uri.replace('amp;', '');
       $('#home_content').load(uri).css("display", "none").fadeIn(500);
}

They switch correctly, but every time i switch to another div, first of all i get current div loaded again, and then switched to another. It looks like delay.

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:57:09+00:00Added an answer on May 24, 2026 at 5:57 pm

    You’re making an asynchronous call to the server but the methods in the chain are executed immediately. The div’s contents are updated only later when the data has been loaded from the server. You must add the fadein method to the callback function of the Ajax call so that it executes only after the contents have been updated.

    $('#home_content').css("display", "none").load( uri, 
        function() { $( '#home_content' ).fadeIn(500) } );
    
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