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Editorial Team
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Asked: 2026-06-04T15:37:01+00:00

I came across some results in a program I was writing that confused me.

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I came across some results in a program I was writing that confused me. It is my understanding parens are not normally needed (i.e. obj.method1.method2 is as good as (obj.method1).method2). In addition all operators are really method calls so I expected them to behave similarly.

So imagine my surprise that "S"+"R".downcase resulted in Sr as did "S".+"R".downcase however "S".send(:+, "R").downcase finally gave me the expected output sr

Is this because the operator shortcuts are treated differently or is there some other mechanic at work here that I am missing?

Edit: The question isn’t about the order of operations that resulted in the answer, that’s obvious. The question was WHY the expression was resolved in that order.

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1 Answer

  1. Editorial Team

    . has higher precedence than + and is evaluated first. ("S"+"R").downcase works too.

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