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Home/ Questions/Q 6099121
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T13:14:12+00:00 2026-05-23T13:14:12+00:00

I came across the statement: outbal.write( (char*) &acc , sizeof( struct status ) );

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I came across the statement:

outbal.write( (char*) &acc , sizeof( struct status ) );

outbal is an object of ofstream and status is a type.

Therefore:

struct status {
  // code
};

status acc;

Talking about the second line I don’t understand the first argument, which is (char*) &acc. What are we doing and how?

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  1. Editorial Team
    Editorial Team
    2026-05-23T13:14:13+00:00Added an answer on May 23, 2026 at 1:14 pm

    (char*)&acc if the address of the variable acc, cast to a char pointer so as to be compatible with ostream::write(). It is that variable that is being written, to the outbal stream, for a length of sizeof(struct status).

    ostream::write takes a memory address and a length and will output that memory to the specified stream. In other words, you’re simply outputting the entire memory contents of the acc variable.

    Your code is similar to:

    struct xyz {int a; float b; void *c};
    
    ostream os("myfile.dat");
    
    struct xyz abc; // 'struct' not technically needed in C++
    
    os.write (  (char *)abc,      sizeof (struct xyz));
    //        <<-memory addr->>   <<-----size----->>
    
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