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Home/ Questions/Q 911303
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T17:11:01+00:00 2026-05-15T17:11:01+00:00

I came across this article on Code Project that talks about using an abstract

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I came across this article on Code Project that talks about using an abstract interface as an alternative to exporting an entire class from a C++ DLL to avoid name mangling issues. The author has a Release() method in his interface definition that is supposed to be called by the user to free the class object’s resources after using it. To automate the calling of this method the author also creates an std::auto_ptr<T>-like class that calls the Release() method before deleting the object.

I was wondering whether the following approach would work instead:

#include <memory>

#if defined(XYZLIBRARY_EXPORT) // inside DLL
#   define XYZAPI   __declspec(dllexport)
#else // outside DLL
#   define XYZAPI   __declspec(dllimport)
#endif  // XYZLIBRARY_EXPORT

// The abstract interface for Xyz object.
// No extra specifiers required.
struct IXyz
{
    virtual int Foo(int n) = 0;

    //No Release() method, sub-class' destructor does cleanup
    //virtual void Release() = 0;

    virtual ~IXyz() {}
};

// Factory function that creates instances of the Xyz object.
// Private function, do not use directly
extern "C" XYZAPI IXyz* __stdcall GetXyz_();

#define GetXyz()      std::auto_ptr<IXyz>( GetXyz_() )

Of course, GetXyz() can be a global function defined in the header instead of a #define. The advantage to this method would be that we don’t need to cook up our own derivative of auto_ptr that calls the Release() method.

Thanks for your answers,
Ashish.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T17:11:02+00:00Added an answer on May 15, 2026 at 5:11 pm

    by doing this, you risk calling delete (in your process, within auto_ptr’s destructor) on an object that is not created by the matching call to new() (that is done inside the factory function, hence inside the dll). Trouble guaranteed, for instance when your dll is compiled in release mode while the calling process in debug mode.

    The Release() method is better.

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