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Home/ Questions/Q 8093223
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T20:27:26+00:00 2026-06-05T20:27:26+00:00

I came across this due to a bug in my code and I’m curious

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I came across this due to a bug in my code and I’m curious why it’s allowed. What reason is there that allows object members to be visible in the constructor initialization list?

#include <stdio.h>

class derived {
  private:
    int * value2;
  public:
    derived();
};

derived::derived()
 : value2(value2){} // Uninitialized self-assignment

int main()
{
  derived thisChild;
}

Clang gives a warning about this but unfortunately g++ does not.

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  1. Editorial Team
    Editorial Team
    2026-06-05T20:27:27+00:00Added an answer on June 5, 2026 at 8:27 pm

    So you can initalise one member using another; this is perfectly fine if the other has already been initialised, or if you’re just using its address to initialise a pointer or reference. For example:

    struct Thingy
    {
        int & r;
        int a;
        int b;
    
        Thingy(int x) :
            r(a),   // OK - a has a valid address, and we're not using the value
            a(x),
            b(a)    // OK - a has been initialised
        {}
    };
    

    It would be rather tricky to allow that and disallow your example.

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