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Home/ Questions/Q 4252814
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T04:51:59+00:00 2026-05-21T04:51:59+00:00

I came across this post and found belisarius’ answer interesting. Wondering whether he someone

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I came across this post and found belisarius’ answer interesting. Wondering whether he someone can post his
complete mma code and give some explanation. In general, my question is about how to achieve this kind of annimation/plotting behavior in mma. It looks amazing to me!

Many thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-21T04:52:00+00:00Added an answer on May 21, 2026 at 4:52 am

    Please tell me if further explanation is needed.

    x[t_] := {Cos@t, Sin@t, .1  t} /; t <= 3 Pi;
    x[t_] := {Cos@t, Sin@t, .3 Pi  (4 - t/Pi)} /; t > 3 Pi;
    plotRange = {{-110, 110}, {-110, 110}, {-10, 110}};
    z1 = ParametricPlot3D[100 x[t], {t, 0, 4 Pi}, PlotRange -> plotRange];
    hel = Import["ExampleData/helicopter.dxf.gz", 
       ViewPoint -> {10, 10, 10}, AlignmentPoint -> {80, 80, 80}];
    
    zz = Table[
       Show[z1, 
        Graphics3D[
         Translate[Rotate[First[hel], t + Pi/2, {0, 0, 1}], 100 x[t]]], 
        PlotRange -> plotRange], {t, 0, 4 Pi, 4 Pi/15}];
    Export["c:\\test.gif", zz, "DisplayDurations" -> .5]
    
    (* Or
     Animate[Show[z1, 
       Graphics3D[
        Translate[Rotate[First[hel], t + Pi/2, {0, 0, 1}], 100 x[t]]], 
       PlotRange -> plotRange], {t, 0, 4 Pi}]
    

    enter image description here

    One could calculate the heli rotation using the curve derivatives. Too lazy to do it right now.

    Edit

    To comply with Sjoerd’s home decoration rules:

    enter image description here

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