I came up with my own little class called TinyVector. And now I’m trying to use std::inner_product on it. But I can’t get it to work and I don’t understand why this does not work.
I’m using Visual Studio 2012.
#include <iostream>
#include <vector>
#include <numeric>
using namespace std;
template<class T, int N>
class TinyVector {
public:
TinyVector() { data = vector<T>(N, 0); }
explicit TinyVector(const T initVal) { data = vector<T>(N, initVal); }
~TinyVector() { data.clear(); }
inline T& operator[](int i) { return data[i]; }
inline T operator[](int i) const { return data[i]; }
inline vector<T>::const_iterator begin() const { return data.begin(); } //Line 15
inline vector<T>::const_iterator end() const { return data.end(); } //Line 16
private:
vector<T> data;
};
template<class T, int N>
inline double dot(const TinyVector<T,N>& A, const TinyVector<T,N>& B)
{
return inner_product(A.begin(), A.end(), B.begin(), 0.0);
}
int main()
{
TinyVector<double, 10> Ty;
for (int i = 0; i < 10; ++i)
Ty[i] = i;
cout << dot(Ty,Ty) << endl;
}
The compiler tells me:
syntax error : missing ‘;’ before identifier ‘begin’ on line 15.
missing type specifier – int assumed. Note: C++ does not support default-int on line 15.
syntax error : missing ‘;’ before identifier ‘end’ on line 16.
missing type specifier – int assumed. Note: C++ does not support default-int on line 16.
But changing vector<T>::const_iterator into vector::const_iterator doesn’t seem like the way to go.
Also changing it to ‘auto’ does not work. This gives me “expected a trailing return type”.
If I delete line 15,16 and 17 and replace A.begin() with A.data.begin() and the next two arguments accoringly, everything is fine.
But why doesn’t my original code work, and how can I get it to work?
You need to write
This is because
vector<T>::const_iteratoris a dependent name (it is dependent on the type parameterT) and so the compiler needs to be told thatvector<T>::const_iteratoris a type (and not, say, anenumvalue or static data member).