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Home/ Questions/Q 7575283
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T16:38:57+00:00 2026-05-30T16:38:57+00:00

I can be given a string in any of these formats: url: e.g http://www.acme.com:456

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I can be given a string in any of these formats:

  • url: e.g http://www.acme.com:456

  • string: e.g http://www.acme.com:456, http://www.acme.com 456, or http://www.acme.com

I would like to extract the host and if present a port. If the port value is not present I would like it to default to 80.

I have tried urlparse, which works fine for the url, but not for the other format. When I use urlparse on hostname:port for example, it puts the hostname in the scheme rather than netloc.

I would be happy with a solution that uses urlparse and a regex, or a single regex that could handle both formats.

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  1. Editorial Team
    Editorial Team
    2026-05-30T16:38:58+00:00Added an answer on May 30, 2026 at 4:38 pm

    I’m not that familiar with urlparse, but using regex you’d do something like:

    p = '(?:http.*://)?(?P<host>[^:/ ]+).?(?P<port>[0-9]*).*'
    
    m = re.search(p,'http://www.abc.com:123/test')
    m.group('host') # 'www.abc.com'
    m.group('port') # '123'
    

    Or, without port:

    m = re.search(p,'http://www.abc.com/test')
    m.group('host') # 'www.abc.com'
    m.group('port') # '' i.e. you'll have to treat this as '80'
    

    EDIT: fixed regex to also match ‘www.abc.com 123’

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