Question

I can call the values of the drop down box from the database, but I can’t save the selected value in a new row within the database. Can someone please tell me where I’m going wrong?

if (isset($_POST["addDestination"]) && $_POST["addDestination"]=="yes")
{
    $countriesName=$_POST["countriesName"];
    $Name=$_POST["Name"];
    $photo=$_POST["photo"];
    $description=$_POST["description"];
    $Airport=$_POST["Airport"];
    $Airport2=$_POST["Airport2"];
    $Airline=$_POST["Airline"];
    $Airline2=$_POST["Airline2"];
    $Airline3=$_POST["Airline3"];
    $Airline4=$_POST["Airline4"];

    $dbQuery= "INSERT INTO destinations VALUES( NULL, '$countriesName', '$Name', '$photo', '$description', '$Airport', '$Airport2', '$Airline', '$Airline2', '$Airline3', '$Airline4')";
    $result= mysql_query($dbQuery,$db);

The html code and php code that call the values in from the database is:

<form id="addDestination" name="addDestination" method="post" action="addDestination.php">
    <input type="hidden" name="addDestination" value="yes">
    <div id="countriesName" class="info"><span class="formLabel">Country (Please select one of the following)</span><br>
    <?php 
      echo "<p></p>";
      $dbQuery="SELECT Name FROM countries order by name asc";
      $dbResult=mysql_query($dbQuery);
      echo "<select name=\"Name\">";
      while ($dbRow=mysql_fetch_array($dbResult)) {
        $Name=$dbRow["Name"];
        echo "<option value='$Name'>$Name</option>";
      }
      echo "</select>";
      echo "<p> </p>";
    ?>
  </div>

When I try to save a selected value, the field in the database stays blank.

Answer 1

I think this might be that rather than:

$countriesName=$_POST["countriesName"];

you may need to use:

$countriesName=$_POST["Name"];

"Name" is the name of your actual HTML select, rather than "countriesName" which is the containing div.