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Home/ Questions/Q 4000868
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T07:50:05+00:00 2026-05-20T07:50:05+00:00

I can connect to a linked server with this: SELECT testNo, soruTuruId, soruNo, cevap

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I can connect to a linked server with this:

SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo
FROM OPENDATASOURCE(‘SQLOLEDB’, ‘Data Source=192.168.150.42;User ID=readerUser;Password=1’).akreditasyon.dbo.tblPerfCevap

But I have to pass the password as parameter. and I try like this:

SET @connectionString = ‘Data Source=192.168.150.42;User ID=readerUser;Password=’+@pw

SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo
FROM OPENDATASOURCE(‘SQLOLEDB’, @connectionString ).akreditasyon.dbo.tblPerfCevap

and

SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo
FROM OPENDATASOURCE(‘SQLOLEDB’, ‘Data Source=192.168.150.42;User ID=readerUser;Password=’+@pw ).akreditasyon.dbo.tblPerfCevap

but didnt work:S

does anyone have an idea?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T07:50:06+00:00Added an answer on May 20, 2026 at 7:50 am

    use exec () function to run the query. Wrap your query into a valid string.

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