Question

I can fetch the menucode from database i can print inside for loop means it prints all menucodes. if i print loop out side means it print only last value

         my code
     JSONArray json = jArray.getJSONArray("mainmenu");

         for ( i = 0; i < json.length(); i++) {

                JSONObject e = json.getJSONObject(i);
            map.put("itemcode", e.getString("menucode"));   //here i print all values  


         }
      list.setOnItemClickListener(new OnItemClickListener() {   

        public void onItemClick(AdapterView<?> arg0, View arg1, int arg2,
                long arg3) {
            System.out.println(map.get("itemcode"));//here i print only last value(here i want print all values how can i do this)
            // TODO Auto-generated method stub
            Intent intent=new Intent(getApplicationContext(),FoodMenu.class);
            startActivity(intent);
        }
    });

out side for loop also i want print all menucodes .. please help me

Answer 1

You are using a map, and you have the same key all the time ("itemcode"), so each insertion overrides the previous insertion to the map, maybe you should just use a List, or use different keys.

Answering the comment by giving examples:

1. Using ArrayList / List:

   List<String> codez = new ArrayList<String>();
   for ( i = 0; i < json.length(); i++) {
       JSONObject e = json.getJSONObject(i);
       codez.add(e.getString("menucode"));
   }
   

2. Using different keys:

   for ( i = 0; i < json.length(); i++) {
       JSONObject e = json.getJSONObject(i);
       map.put("itemcode" + i, e.getString("menucode"));
   }
   

Last thing – you cannot have two identical keys in a map, it defeats its purpose, and it’s useless. If you are not going to get the values with by the key, and if the key is not used, you shouldn’t use a map in first place.