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Home/ Questions/Q 8845945
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T11:51:22+00:00 2026-06-14T11:51:22+00:00

I can get a static resource like this with AppEngine: InputStream is = getServletContext().getResourceAsStream(/WEB-INF/config/Reports.xml);

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I can get a static resource like this with AppEngine:

InputStream is = 
    getServletContext().getResourceAsStream("/WEB-INF/config/Reports.xml");

However, I need to get this static resource URI and pass it on to a Java class which is not a Servlet.

What is the strategy to pass URI if this is the case?

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  1. Editorial Team
    Editorial Team
    2026-06-14T11:51:23+00:00Added an answer on June 14, 2026 at 11:51 am
    URI uri = 
        getServletContext().getResource("/WEB-INF/config/Reports.xml").toURI();
    
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