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Home/ Questions/Q 6917281
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T09:42:38+00:00 2026-05-27T09:42:38+00:00

I can launch my app as standalone app (for example from command line) or

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I can launch my app as standalone app (for example from command line) or one specific way — it is directly “from” source code, i.e. using IntelliJ.

Is there a way to detect if app was launched from IntelliJ or not? Only this, binary decision.

Workarounds are plenty, adding extra option when launching, however I am looking for direct solution, like this for C#
How to know that the application is launched by debugger (VisualStudio) C#

The solution can be valid for any IDE, but must be valid at least for IntelliJ.

Little update

For those (including me) seeking ready to use code (Scala code):

object ProgramInfo
{
  val isStandaloneApp = sun.management.ManagementFactory.getRuntimeMXBean().getInputArguments.isEmpty
  val isDebugMode = scala.collection.JavaConversions.iterableAsScalaIterable(sun.management.ManagementFactory.getRuntimeMXBean().getInputArguments).exists(it => it.startsWith("-agentlib"))
}

It won’t work in complex cases, but if you don’t pass ton of parameters to JVM, it’s just fine.

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  1. Editorial Team
    Editorial Team
    2026-05-27T09:42:38+00:00Added an answer on May 27, 2026 at 9:42 am

    I have used the below in the past to check the debug settings. You could use something similar

    ManagementFactory.getRuntimeMXBean().getInputArguments()
    

    enter image description here

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