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Home/ Questions/Q 8030583
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T00:49:03+00:00 2026-06-05T00:49:03+00:00

I can loop through a Python (v.2.6) list without specifying indices, using the following

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I can loop through a Python (v.2.6) list without specifying indices, using the following “Pythonic” syntax:

the_list = [2, 3, 5, 7, 11, 13]
for item in the_list:
    print item + 2

But if I want to perform an operation on two consecutive indices, I think I then have to specify index numbers, with a corresponding change to the range of the for loop:

the_list = [2, 3, 5, 7, 11, 13]
for i in xrange(len(the_list)-1):
    print the_list[i] + the_list[i+1]

Is that correct? Or is there a way to remain Pythonic and avoid using the expression xrange(len(the_list)-1)?

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  1. Editorial Team
    Editorial Team
    2026-06-05T00:49:05+00:00Added an answer on June 5, 2026 at 12:49 am

    I’m fond of the pairwise recipe as listed in the docs to the itertools module:

    def pairwise(iterable):
        "s -> (s0,s1), (s1,s2), (s2, s3), ..."
        a, b = tee(iterable)
        next(b, None)
        return izip(a, b)
    

    Then…

    for x, x_next in pairwise(the_list):
        ...
    

    You can also just zip the list with a slice of itself:

    for x, x_next in zip(the_list, the_list[1:]):
        ...
    
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