Question

I can use pointer for one-dimension array for function, but I don’t know use the same technique for two-dimension array.

Here is my example code :

     int main(){
          int b[10]; //initialize b
          Print(b);
          int a[10][10]; //initialize a
          Print2(a);
        }

        void Print(int*b){  
           for(int i=0; i<10; i++)
              printf("%d\n",*(b+i));
        }

    // I want to use same technique here
    // but i have met error 

        void Print2(int*a){
           for(int i=0; i<10; i++)
              for(int j=0; j<10; j++)
                  printf("%d\n",*(*(a+i)+j));  // error at this line
        }

Please help me how to use same technique of one-dimension array for two-dimension array.

Thanks 🙂

Answer 1

destroy the inner * and multiply i with 10 then add j

 printf("%d\n",*((a+i*10)+j));

because going “downwards” in a 2d matrix, you go through dimension-1(10 in this example) elements.

for 3d:

 printf("%d\n",*(a+i*100+j*10+k));

for N-dimensions:

  *(a+i*(size of i-dimension)+j*(size of j dim)+......+last index)