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Home/ Questions/Q 6129159
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:42:35+00:00 2026-05-23T16:42:35+00:00

I cannot ask for help on their forums, but i’ve been at this for

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I cannot ask for help on their forums, but i’ve been at this for 3 hours now. Spoilers Below I don’t understand what i’m doing wrong. The question is:

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.

Here’s my equation I made.

for($total = 0, $f = 5, $t = 3; $t < 1000; $t+=3){

    if($f < 1000)
    {
        $total += $f + $t;
        echo "Five: $f, Three: $t = $total<br />";
        $f += 5;
    }
    else
    {
        $total += $t;
        echo "Five: $f, Three: $t = $total<br />";
    }
}

The answer is:233168. Where’s my error?

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:42:35+00:00Added an answer on May 23, 2026 at 4:42 pm

    You are counting numbers that are divisible both by 3 and 5 twice.

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