I cannot find any example on how to use the pattern= parameter in list.files

Question

Editorial Team

Asked: May 28, 20262026-05-28T13:30:27+00:00 2026-05-28T13:30:27+00:00

I cannot find any example on how to use the pattern= parameter in list.files for more complex operations.

I would like to get all the files that include either ‘XM’ or ‘EM’ and are of the .cvs type

Can someone please help me.

I was trying something like

list.files(path='.', pattern="[XM | EM] & csv")

but it is definitely wrong

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Editorial Team · Answer 1 · 2026-05-28T13:30:29+00:00

Editorial Team

try this:

list.files(path='.', pattern="(XM|EM).*\\.csv$")

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