Question

I cannot understand why the code below compiles.

public void Overflow()
{
    Int16 s = 32767;
    s = (Int16)  (s + 1);
}

At the compile time it is obvious that (s+1) is not a Int16 anymore as we know the value of s.

And CLR allows casting to :

• To its own type
• Or any of the base-types (because it is safe)

As Int32 is not Int16 and Int16 is not base type of Int32.

Question: So why the compiler does not fail for the casting above? Can you please explaint it from the CLR and compiler point of view?

Thanks

Answer 1

The type of the expression s + 1 is Int32 – both operands are converted to Int32 before the addition is performed. So your code is equivalent to:

public void Overflow()
{
    Int16 s = 32767;
    s = (Int16)  ((Int32) s + (Int32) 1);
}

So the overflow only actually occurs in the explicit cast.

Or, to put it another way: because the language specification says so. You should describe one of:

• Why you think the compiler is violating the language specification
• The exact change you’re proposing to the language specification

EDIT: Just to make things really clear (based on your comments), the compiler wouldn’t allow this:

s = s + 1;

when s is an Int16 whatever the value of s might be known to be. There’s no Int16 operator+ (Int16, Int16) operator – as shown in section 7.8.4 of the C# 4 spec, the integer addition operators are:

int operator +(int x, int y);
uint operator +(uint x, uint y);
long operator +(long x, long y);
ulong operator +(ulong x, ulong y);