Question

I can’t believe I’m getting so stuck on what seems like such a simple query.

I need to get back the User of a Log for a given Project which has the maximum DateLogged value. I’ve rewritten it a million ways but this is the way which expresses what I want the clearest –

SELECT L.User
FROM Log AS L
WHERE L.Id = 24
GROUP BY L.ProjectId
HAVING MAX(L.DateLogged) = L.DateLogged

But that throws a “Column ‘Log.DateLogged’ is invalid in the HAVING clause because it is not contained in either an aggregate function or the GROUP BY clause.” But I don’t want it grouped by DateLogged, nor do I want it in an aggregate function.

Answer 1

I think that if you use L.Id = 24, you are going to get only ONE row back. IMO you should be filtering by the L.User or L.UserId, not the L.Id

For a list of all projects, this is what you can do.

SELECT L.User, L.ProjectId, MAX (L.DateLogged) as DateLogged
FROM Log AS L
WHERE L.User = @YourUserNameGoesHere
GROUP BY L.User, L.ProjectId

For a single project that you know the project detail for, just use an ORDER BY

SELECT TOP 1 L.User, L.DateLogged
FROM Log AS L
WHERE L.User = @YourUserNameGoesHere
AND L.ProjectId = @YourProjectIdGoesHere
ORDER BY L.DateLogged DESC