Question

I can’t get my authors from my php quotes

i have a quotes table:
id, quote, aid

i have a author table:
id, name, etc…

<?php

$DB_SERVER = "localhost";
$DB_USER = "root";
$DB_PASS = "";
$DB_NAME = "test";
$con = mysql_connect($DB_SERVER, $DB_USER, $DB_PASS);
mysql_select_db($DB_NAME);

$sql = mysql_query("SELECT * FROM quotes WHERE id = ".$_GET['id'], $con);
$row = mysql_fetch_row($sql);

$sql = mysql_query("SELECT * FROM author where aid = " . $row[1], $con);
$row = mysql_fetch_row($sql); 


var_dump($row);

now i get this error
Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in /var/www/domain.com/php.php on line 14
NULL

Answer 1

if you print_r($row); after the first query you will see something like:

Array
(
    [0] => id
    [1] => quote 
    [2] => aid
)

then on your second query you use $row[1] which is the quote (string) and not the number.

$sql = mysql_query("SELECT * FROM author where aid = " . $row[1], $con);

if you echo the error (using mysql_error($con)) you will see something:

You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near ‘a quote

instead of using mysql_fetch_row use mysql_fetch_assoc and the key of the array will be the name of the column. This way, it’s very easy to retrieve data. And don’t forget to close your connection.

<?php
$_GET['id'] = 1;
$DB_SERVER = "localhost";
$DB_USER = "root";
$DB_PASS = "";
$DB_NAME = "test";
$con = mysql_connect($DB_SERVER, $DB_USER, $DB_PASS);
mysql_select_db($DB_NAME);
$sql = mysql_query("SELECT * FROM quotes WHERE id = " . (int)$_GET['id'], $con); // or you can use the mysql_real_escape_string
if(!$sql) {
  echo mysql_error($con);
}
$row = mysql_fetch_assoc($sql);
mysql_free_result($sql);

$sql = mysql_query("SELECT * FROM author where id = " . (int)$row['aid'], $con);
if(!$sql) {
  echo mysql_error($con);
}
$row = mysql_fetch_assoc($sql); 
mysql_free_result($sql);

print_r($row);
mysql_close($con);