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Home/ Questions/Q 6105911
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T14:01:22+00:00 2026-05-23T14:01:22+00:00

I can’t understand why I can’t use a variable for the regex string. See

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I can’t understand why I can’t use a variable for the regex string. See link: http://jsfiddle.net/nmWuw/1/

It works without the variable but not when a variable is used for the regex. I escaped my backslashes as well. Output should be ‘1,234,567,890’.

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  1. Editorial Team
    Editorial Team
    2026-05-23T14:01:23+00:00Added an answer on May 23, 2026 at 2:01 pm
    var regex = "/\\d(?=(?:\\d{3})+(?!\\d))/g, '$&,'";
    

    That is a string. It is not a regexp object and a replacement string. When it is passed to replace, it is one parameter, not two. You need to pass both parameters separately:

    var regex = /\d(?=(?:\d{3})+(?!\d))/g;
    var replace = '$&,';
    var num = 1234567890;
    
    alert(String(num).replace(/\d(?=(?:\d{3})+(?!\d))/g, '$&,'));
    alert(String(num).replace(regex, replace));
    alert(regex);
    

    http://jsfiddle.net/nmWuw/3/


    Note that you could define them in one call, if you really wanted to, using an array and apply:

    var regex = [/\d(?=(?:\d{3})+(?!\d))/g, '$&,'];
    alert(String.prototype.replace.apply(num, regex));
    

    http://jsfiddle.net/nmWuw/6/

    This is hardly a good idea, however — it’s much harder to read and much less intuitive.

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